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11x^2+7x-120=0
a = 11; b = 7; c = -120;
Δ = b2-4ac
Δ = 72-4·11·(-120)
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5329}=73$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-73}{2*11}=\frac{-80}{22} =-3+7/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+73}{2*11}=\frac{66}{22} =3 $
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